Not sure how to go about this. Can I just rationalize either the numerator or denominator? lim (√2-x) - (√8-4x) x->2 (√3x+3) - (√11-x)
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Originally Posted by Neconine Not sure how to go about this. Can I just rationalize either the numerator or denominator? lim (√2-x) - (√8-4x) x->2 (√3x+3) - (√11-x) Hi The numerator is
Originally Posted by Neconine Not sure how to go about this. Can I just rationalize either the numerator or denominator? lim (√2-x) - (√8-4x) x->2 (√3x+3) - (√11-x) first, note that this limit should be one-sided since the domain of the rational expression is as , the numerator approaches 6 and the denominator approaches 0 ... the limit does not exist.
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