Results 1 to 6 of 6

Math Help - position, acceleration, velocity

  1. #1
    Junior Member
    Joined
    Sep 2008
    From
    houston
    Posts
    25

    position, acceleration, velocity

    can anybody help me on my calc problem? i don't quite understand it.

    The position of a particle at time t sec is s=t^3-6t^2+9t. find the particles acceleration each time the velocity is zero.

    thank you.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,621
    Thanks
    426
    Quote Originally Posted by FinalFantasy9291 View Post
    can anybody help me on my calc problem? i don't quite understand it.

    The position of a particle at time t sec is s=t^3-6t^2+9t. find the particles acceleration each time the velocity is zero.

    thank you.
    you are given s(t).

    find v(t) = s'(t)

    also find a(t) = v'(t) = s''(t)

    set v(t) = 0, solve for t, then determine a(t) for those time(s)
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Sep 2008
    From
    houston
    Posts
    25
    could you start the problem out for me? i still don't really know how to start.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,621
    Thanks
    426
    Quote Originally Posted by FinalFantasy9291 View Post
    could you start the problem out for me? i still don't really know how to start.
    are you saying that you do not know how to find the derivative of a polynomial function?
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member
    Joined
    Sep 2008
    From
    houston
    Posts
    25
    ooh! okay. well i took the derivative of s(t) and then i took the double derivative.

    the double is 6t-12 right?

    and then i set s'(t) to 0 so i got t=3 and t=1

    then i pluged them both into a(t) and got 6 and -6.

    did i do it right?
    Follow Math Help Forum on Facebook and Google+

  6. #6
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,621
    Thanks
    426
    Quote Originally Posted by FinalFantasy9291 View Post
    ooh! okay. well i took the derivative of s(t) and then i took the double derivative.

    the double is 6t-12 right?

    and then i set s'(t) to 0 so i got t=3 and t=1

    then i pluged them both into a(t) and got 6 and -6.

    did i do it right?
    yes
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. position, velocity, and acceleration problem
    Posted in the Calculus Forum
    Replies: 4
    Last Post: March 19th 2010, 07:33 AM
  2. Acceleration from position-time
    Posted in the Math Topics Forum
    Replies: 1
    Last Post: March 15th 2010, 09:52 AM
  3. Position, Velocity, Acceleration problem
    Posted in the Calculus Forum
    Replies: 3
    Last Post: March 6th 2010, 09:29 AM
  4. Replies: 5
    Last Post: June 1st 2009, 05:50 AM
  5. Replies: 3
    Last Post: May 1st 2009, 01:47 PM

Search Tags


/mathhelpforum @mathhelpforum