can anybody help me on my calc problem? i don't quite understand it. The position of a particle at time t sec is s=t^3-6t^2+9t. find the particles acceleration each time the velocity is zero. thank you.
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Originally Posted by FinalFantasy9291 can anybody help me on my calc problem? i don't quite understand it. The position of a particle at time t sec is s=t^3-6t^2+9t. find the particles acceleration each time the velocity is zero. thank you. you are given s(t). find v(t) = s'(t) also find a(t) = v'(t) = s''(t) set v(t) = 0, solve for t, then determine a(t) for those time(s)
could you start the problem out for me? i still don't really know how to start.
Originally Posted by FinalFantasy9291 could you start the problem out for me? i still don't really know how to start. are you saying that you do not know how to find the derivative of a polynomial function?
ooh! okay. well i took the derivative of s(t) and then i took the double derivative. the double is 6t-12 right? and then i set s'(t) to 0 so i got t=3 and t=1 then i pluged them both into a(t) and got 6 and -6. did i do it right?
Originally Posted by FinalFantasy9291 ooh! okay. well i took the derivative of s(t) and then i took the double derivative. the double is 6t-12 right? and then i set s'(t) to 0 so i got t=3 and t=1 then i pluged them both into a(t) and got 6 and -6. did i do it right? yes
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