show that if $\displaystyle 0<a<b, then (a^n + b^n)^{1/n} --> b$

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- Mar 21st 2010, 09:53 AMwopashuishow the limit is b
show that if $\displaystyle 0<a<b, then (a^n + b^n)^{1/n} --> b$

- Mar 21st 2010, 09:59 AMPlato
- Mar 21st 2010, 10:24 AMwopashui
- Mar 21st 2010, 11:03 AMdrumist
- Mar 21st 2010, 11:40 AMchiph588@