hi! the question and my work are both attached . Can someone please help me. Thanks
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Originally Posted by hoger hi! the question and my work are both attached . Can someone please help me. Thanks well, there is a mistake in your first line of work ... $\displaystyle \frac{1}{2x^2-1} \ne \frac{1}{2} \cdot \frac{1}{x^2-1}$ try this ... $\displaystyle \frac{1}{2x^2-1} = \frac{1}{(\sqrt{2} x - 1)(\sqrt{2} x + 1)} = \frac{A}{\sqrt{2} x - 1} + \frac{B}{\sqrt{2} x + 1}$
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