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Math Help - Improper Integral check

  1. #1
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    Improper Integral check

    hi!

    the question and my work are both attached .
    Can someone please help me.

    Thanks
    Attached Thumbnails Attached Thumbnails Improper Integral check-ccf20100321_00000.jpg  
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  2. #2
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    Quote Originally Posted by hoger View Post
    hi!

    the question and my work are both attached .
    Can someone please help me.

    Thanks
    well, there is a mistake in your first line of work ...

    \frac{1}{2x^2-1} \ne \frac{1}{2} \cdot \frac{1}{x^2-1}


    try this ...

    \frac{1}{2x^2-1} = \frac{1}{(\sqrt{2} x - 1)(\sqrt{2} x + 1)} = \frac{A}{\sqrt{2} x - 1} + \frac{B}{\sqrt{2} x + 1}
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