find the limit if it's converge

**wopashui** · March 20th 2010, 04:30 PM

$2^n/(4^n+1)$

i know it's converge to 0, but I have trouble dealing with the n expontial, can someone tell me the general methof for finding the limits for $a^n/(b^n + 1)$

**Random Variable** · March 20th 2010, 04:53 PM

$\lim \frac{2^{n}}{1+4^{n}} =\lim \frac{\frac{2^{n}}{4^{n}}}{\frac{1}{4^{n}}+\frac{4 ^{n}}{4^{n}}}$

$\lim \frac{\frac{1}{2^{n}}}{\frac{1}{4^{n}} + 1} = \frac{0}{0+1} = 0$

**wopashui** · March 20th 2010, 06:03 PM

thanks, i have got another one, $n^2/\sqrt{2n^4+1}$

how do I deal with the squre root?

**Random Variable** · March 20th 2010, 06:10 PM

Originally Posted by wopashui

thanks, i have got another one, $n^2/\sqrt{2n^4+1}$

how do I deal with the squre root?

Divide the numerator and the denominator by $n^{2}$ . When you bring the $n^{2}$ inside of the radical it becomes $n^{4}$

**wopashui** · March 20th 2010, 09:33 PM

Originally Posted by Random Variable

Divide the numerator and the denominator by $n^{2}$ . When you bring the $n^{2}$ inside of the radical it becomes $n^{4}$

hmm, I dun quite understand it, can you show me the steps please?

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