$\displaystyle 2^n/(4^n+1)$

i know it's converge to 0, but I have trouble dealing with the n expontial, can someone tell me the general methof for finding the limits for $\displaystyle a^n/(b^n + 1)$

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- Mar 20th 2010, 04:30 PMwopashuifind the limit if it's converge
$\displaystyle 2^n/(4^n+1)$

i know it's converge to 0, but I have trouble dealing with the n expontial, can someone tell me the general methof for finding the limits for $\displaystyle a^n/(b^n + 1)$ - Mar 20th 2010, 04:53 PMRandom Variable
$\displaystyle \lim \frac{2^{n}}{1+4^{n}} =\lim \frac{\frac{2^{n}}{4^{n}}}{\frac{1}{4^{n}}+\frac{4 ^{n}}{4^{n}}}$

$\displaystyle \lim \frac{\frac{1}{2^{n}}}{\frac{1}{4^{n}} + 1} = \frac{0}{0+1} = 0$ - Mar 20th 2010, 06:03 PMwopashui
thanks, i have got another one, $\displaystyle n^2/\sqrt{2n^4+1}$

how do I deal with the squre root? - Mar 20th 2010, 06:10 PMRandom Variable
- Mar 20th 2010, 09:33 PMwopashui