Hello, nozpoz!
You dropped some exponents . . .
Differentiate with the Quotient Rule: .
We have: .
. . . . . . .
. . . . . . .
. . . . . . .
which is equal to: .
I have a maths B (Grade 11 & 12 Advanced) exam on monday and im studying up for my whole weekend. D=
Anyway one question that I need help for is:
y = tan^2 3x
The answer I got in the end after using the quotient rule was
dy/dx = 6cos3x * cos^2 3x + sin^2 3x * 6sin 3x / cos^3 3x
The denominator is correct but the answer says that the numerator is 6sin3x
Can you please help me using tanx = sinx / cosx not sec^2 x
Thanks to anyone who can help me =)