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Math Help - [SOLVED] Limits of sequence of functions

  1. #1
    is up to his old tricks again! Jhevon's Avatar
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    [SOLVED] Limits of sequence of functions

    Can someone help me with this problem, please?
    Attached Thumbnails Attached Thumbnails [SOLVED] Limits of sequence of functions-lim1.gif  
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    Quote Originally Posted by Jhevon View Post
    Can someone help me with this problem, please?
    Hello, Jhevon,

    I've attached an image of the calculations to b) and c). Part a) needs some more typing but I hope I can post my considerations to a) pretty soon:
    Attached Thumbnails Attached Thumbnails [SOLVED] Limits of sequence of functions-altern_cosfolge.gif  
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    is up to his old tricks again! Jhevon's Avatar
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    Based on how earboth did parts b) and c), here's how i think a) should be done. Am i correct?
    Attached Thumbnails Attached Thumbnails [SOLVED] Limits of sequence of functions-lim1.gif  
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    Hi, Jhevon,

    it's me again.

    I did a) in a different way than you did (to be exact you should use probably absolute values)
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by earboth View Post
    Hi, Jhevon,

    it's me again.

    I did a) in a different way than you did (to be exact you should use probably absolute values)
    would i have to state i am approximating cos(x) with a/b. since there are values for cos(x) that are irrational and can't be written as a rational function
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    Senior Member ecMathGeek's Avatar
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    Quote Originally Posted by Jhevon View Post
    would i have to state i am approximating cos(x) with a/b. since there are values for cos(x) that are irrational and can't be written as a rational function
    In his example, earboth stated that a and b are elements of irrational numbers.
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by ecMathGeek View Post
    In his example, earboth stated that a and b are elements of irrational numbers.
    Ah yes, he said they are from the reals, which includes the irrationals. ok, thanks
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