Hi.
Can't seem to get this right. Can anyone please help me.
Derivative of the function
f(x)=xe^x^2
You'll need to use a combination of the product and chain rules.
$\displaystyle f(x) = x\,e^{x^2}$
$\displaystyle f'(x) = x\,(e^{x^2})' + e^{x^2}\,(x)'$
$\displaystyle = x(2x)(e^{x^2}) + e^{x^2}(1)$
$\displaystyle = 2x^2\,e^{x^2} + e^{x^2}$
$\displaystyle = e^{x^2}(2x^2 + 1)$