Usually, to find concavity, you must set the second derivative equal to zero. Use those x values to find where it is positive, where it is negative. Positive means concave up, negative means concave down.
This is the problem:
I have to find:
A) critical values = 0
B) where f(x) is increasing = (0,inf)
C) where f(x) is decreasing = (-inf,0)
D) local maxima at x = none
E) local minima at x = 0
F) concave up =
G) concave down =
H) inflection point(s) at x =
I) horizontal asymptote(s) y = 3
J) vertical asymptote(s) x = none
I was able to figure out everything excluding F, G, and H -as you may have noticed. I know that I have to find the second derivative of the original function however when I tried this was what I got:
Would someone please help me?
[drumist] yup that was what i got for the first derivative.where i messed up was that i didn't take the derivative of for g prime.i fixed my error and found the inflection point to be and it is correct.i plugged in points near the interval and found that it is concave up at and concave down at however it said i was wrong.i dont understand how its wrong