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Math Help - [SOLVED] Radius and interval of convergence 2

  1. #1
    is up to his old tricks again! Jhevon's Avatar
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    [SOLVED] Radius and interval of convergence 2

    Please check my work, need help with this one
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  2. #2
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    Well,

    1/n^(sqrt(n)) <= 1/n^2 for sufficiently large n, that is, n>=4.

    Use comparasion test.

    I get that [-1,1] is interval of convergence.
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