Given $\displaystyle V=\frac{4}{3}{\pi}r^3$.Use the differentiation method to find the small change in v when r increases from 3 to 3.01.
Follow Math Help Forum on Facebook and Google+
Originally Posted by mastermin346 Given $\displaystyle V=\frac{4}{3}{\pi}r^3$.Use the differentiation method to find the small change in v when r increases from 3 to 3.01. $\displaystyle \frac{\Delta V(r)}{\Delta r} = \frac{V(r + h) - V(r)}{h}$. Here $\displaystyle h = 0.01$. Substitute everything in and see how you go.
Originally Posted by Prove It $\displaystyle \frac{\Delta V(r)}{\Delta r} = \frac{V(r + h) - V(r)}{h}$. Here $\displaystyle h = 0.01$. Substitute everything in and see how you go. can u show step by step?
Originally Posted by mastermin346 can u show step by step? I'm sure you can have a go. If you get stuck, show what you have done then I'll help you fix it.
View Tag Cloud