derivative - using quotient rule

**calculus0** · March 18th 2010, 01:45 AM

how do I get the derivative of:

-4x
---------
(x^2-1)^2

the answer is

12x^2+4
--------------
(x^2-1)^3

using the quotient rule, it seems simple enough but I cant seem to cancel out properly. Thanks!

**tom@ballooncalculus** · March 18th 2010, 02:06 AM

Just in case a picture helps...

... where

... is the chain rule, wrapped inside...

... the product rule. Straight continuous lines differentiate downwards (integrate up) with respect to x, and the straight dashed line similarly but with respect to the dashed balloon expression (the inner function of the composite which is subject to the chain rule).

The general drift is...

Similar to the quotient rule, but no automatic squaring of the denominator.
_________________________________________

Don't integrate - balloontegrate!

Balloon Calculus; standard integrals, derivatives and methods

Balloon Calculus Drawing with LaTeX and Asymptote!

**Prove It** · March 18th 2010, 02:07 AM

Originally Posted by calculus0

how do I get the derivative of:

-4x
---------
(x^2-1)^2

the answer is

12x^2+4
--------------
(x^2-1)^3

using the quotient rule, it seems simple enough but I cant seem to cancel out properly. Thanks!

$y = \frac{-4x}{(x^2 - 1)^2}$

$\frac{dy}{dx} = \frac{(x^2 - 1)^2\,\frac{d}{dx}(-4x) - (-4x)\,\frac{d}{dx}[(x^2 - 1)^2]}{[(x^2 - 1)^2]^2}$

$= \frac{-4(x^2 - 1)^2 + 4x(2x)(2)(x^2 - 1)}{(x^2 - 1)^4}$

$= \frac{-4(x^2 - 1)^2 + 16x^2(x^2 - 1)}{(x^2 - 1)^4}$

$= \frac{(x^2 - 1)[-4(x^2 - 1) + 16x^2]}{(x^2 - 1)^4}$

$= \frac{-4x^2 + 4 + 16x^2}{(x^2 - 1)^3}$

$= \frac{12x^2 + 4}{(x^2 - 1)^3}$

$= \frac{4(3x^2 + 1)}{(x^2 - 1)^3}$ .

**TKHunny** · March 18th 2010, 02:08 AM

Next time, show your efforts. Someone will be pleased to help you whereever you wander off.

**Sudharaka** · March 18th 2010, 02:13 AM

Dear calculus0,

By the time I typed the answer it had already been given by other members. Hope these answers will help you.

**calculus0** · March 18th 2010, 02:18 AM

THANKS! everyone.. that was so fast.

Math Help - derivative - using quotient rule

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