Trig Derivative Q
Find points on the function f(x) = 2sinx + sin²x for when the tangent line is horizontal.
so i found the derivative of that function, which is
f'(x) = 2cosx + 2sinxcosx
what do i do now? set f'(x) to 0? i tried that, but the answer key says that the answer is
(π/2 + 2nπ, 3), (3π/2 + 2nπ, -1)
what does that notation mean? i am confused.. thx
thanks, i get that part now, but do you know what the 3 and -1 mean? How did those y-values come about?
Originally Posted by skeeter
plug the x-value solutions into the original function.
Originally Posted by mneox