I am stuck on this question, I'm supposed to integrate the velocity equation right? I got 6t^2 + C, is that right? I've attached the question as an image.

Printable View

- Mar 17th 2010, 09:54 AMLeitzgeVelocity, Displacement
I am stuck on this question, I'm supposed to integrate the velocity equation right? I got 6t^2 + C, is that right? I've attached the question as an image.

- Mar 17th 2010, 10:13 AMskeeter
- Mar 17th 2010, 11:01 AMLeitzge
I don't know... could you show me how you did that please?

- Mar 17th 2010, 11:08 AMskeeter
- Mar 17th 2010, 11:10 AMLeitzge
yeah

- Mar 17th 2010, 11:24 AMskeeter
for $\displaystyle k$ a konstant ...

$\displaystyle \int e^{kt} \, dt = \frac{1}{k}e^{kt} + C$