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Math Help - Integrating (2x^2 -3)/x(x^2 +4

  1. #1
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    Integrating (2x^2 -3)/x(x^2 +4

    I'm stuck on this problem. I've been playing around, and I can't seem to figure out a way to start it. Is Heaviside the way to go about it or is there some easy simplification I'm not seeing?

    Thanks in advance,

    <br />
\int \frac{2x^2-3}{x(x^2+4)}*dx<br />
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  2. #2
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    Hello, maxreality!

    \int \frac{2x^2-3}{x(x^2+4)}\,dx

    I'd use Partial Fractions . . .

    . . \frac{2x^2-3}{x(x^2+4)} \;=\;\frac{A}{x} + \frac{Bx+C}{x^2+4}


    You should get: . A \,=\,-\frac{3}{4},\;B \,=\,\frac{11}{4}

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  3. #3
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    Ah hah! I didn't realize Bx + C is for quadratics. Thanks!
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