Find the equation for the tangent plane to the surface x^2+3xyz+y^2=-5z^2 at the point (1,1,1). I found the answer to be x+y+3z=5 but my solution manual says -5x-5y+7z=-3.
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Originally Posted by joepinsley Find the equation for the tangent plane to the surface x^2+3xyz+y^2=-5z^2 at the point (1,1,1). I found the answer to be x+y+3z=5 but my solution manual says -5x-5y+7z=-3. It should be (no negative sign before ). Then Plug in to get So it's (or if you prefer).
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