Is it correct if i do this: and then solve?
and then let u = 8-6x and du=-6
then the answer comes to
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It's all correct
thank you, here is another one (I have a test on Friday so I'm trying to do as many problems as I can)
I let u = 6x and du = 6dx
the answer I end up with is:
And what about integrating the constant ? The integral of 1 is x, the integral of 3/4 will be...
But according to your answer, would the integral rather be ? In which case, it's correct - again
oops no you were right I did it wrong but thanks for pointing that out
the answer should be:
No, it looks like you forgot du=6 dx
Otherwise, it's correct.
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