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Math Help - Converge or diverge

  1. #1
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    Converge or diverge

    <br />
\sum\limits_{n = 2}^\infty  {1/ n(ln . n)^2 }<br /> <br /> <br />

    i am stuck ......

    Converge or diverge-capture.png
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  2. #2
    MHF Contributor Drexel28's Avatar
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    Quote Originally Posted by racewithferrari View Post
    <br />
\sum\limits_{n = 2}^\infty  {1/ n(ln . n)^2 }<br /> <br /> <br />

    i am stuck ......

    Click image for larger version. 

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    Cauchy's condensation test.
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  3. #3
    MHF Contributor chisigma's Avatar
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    Also in this case the 'integral test' works... You have only to consider that...

    \int \frac{dx}{x\cdot \ln^{2} x} = - \frac{1}{\ln x} + c (1)

    Kind regards

    \chi \sigma
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