1. ## Converge or diverge

$
\sum\limits_{n = 2}^\infty {1/ n(ln . n)^2 }

$

i am stuck ......

2. Originally Posted by racewithferrari
$
\sum\limits_{n = 2}^\infty {1/ n(ln . n)^2 }

$

i am stuck ......

Cauchy's condensation test.

3. Also in this case the 'integral test' works... You have only to consider that...

$\int \frac{dx}{x\cdot \ln^{2} x} = - \frac{1}{\ln x} + c$ (1)

Kind regards

$\chi$ $\sigma$