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Math Help - sparametric equations

  1. #1
    Member
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    sparametric equations

    Hi:
    I have done part a for this parametric equation question. Before I continue to part b could somebody please check I have succeeded with part a.
    thank you

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  2. #2
    MHF Contributor
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    You have done part (a) correctly. For part (b), you are given that the slope of the normal to the curve is -1/2, which means that the slope of the tangent (which is equal to the value of the derivative) at that point is 2.

    Therefore, solve for t:

    \frac{2(6e^{4t} - 1)}{18e^{2t} - 1} = 2
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  3. #3
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    here it is. Seems a little long winded. Have I done correct and is this the best way?
    thanks

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