i need help finding a convergent geometric series that converges to 3.

i know the formula for a geometric sreries is the sum cr^n, and that if the absolute value of r < 1 it converges to zero...but i dont know how to make one converge to 3.

would this converge to 3? sum 3(2/3)^n, since 2/3 will go to zero and then the c value of 3 will make it converge to 3?

thanks for any help