i need help finding a convergent geometric series that converges to 3.
i know the formula for a geometric sreries is the sum cr^n, and that if the absolute value of r < 1 it converges to zero...but i dont know how to make one converge to 3.
would this converge to 3? sum 3(2/3)^n, since 2/3 will go to zero and then the c value of 3 will make it converge to 3?
thanks for any help
For your problem, you want to find a two constant such that :
choose any value for r such that (to make the series coverges) then put this value in the last equation and solve it for a.
Once you have you can put them in the general form of the geometric series to get the desired series.