# Thread: Help With Antiderivative

1. ## Help With Antiderivative

If f is the function defined by f(x)=cuberoot(x^2+4x) and g is the antiderivative of f such that g(5)=7, then g(1)=

A)-3.882
B)-3.557
C)1.710
D) 3.557
E) 3.882

I really have no idea how to take than antiderivative, I don't even know if its necessary to take it

2. Originally Posted by rawkstar
If f is the function defined by f(x)=cuberoot(x^2+4x) and g is the antiderivative of f such that g(5)=7, then g(1)=

A)-3.882
B)-3.557
C)1.710
D) 3.557
E) 3.882

I really have no idea how to take than antiderivative, I don't even know if its necessary to take it
looks like a calculator active problem to me.

$g(5) - g(1) = \int_1^5 f(x) \, dx$

$g(1) = g(5) - \int_1^5 f(x) \, dx$

use the fnint feature of your calculator.

3. wow you make it look so easy
Thank you much

### if f(x)=(x^2 x)^1/3 and g(x) is integral of f(x) and g(5)=7.find g(1)

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