If you have: (1/4)(1/1+(x-1)) would this be true: a=1 and r=-4(x-1) ?
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Originally Posted by helpplz If you have: (1/4)(1/1+(x-1)) would this be true: a=1 and r=-4(x-1) ? not quite ... $\displaystyle \frac{1}{4} \cdot \frac{1}{1 - (1-x)} = \frac{1}{4} \left[1 + (1-x) + (1-x)^2 + ... \right]$ ... with the restriction $\displaystyle |1-x| < 1$
Thanks! And if you used x-1 instead, it would look the same except with alternating signs, right?
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