Thread: Integrals - Volume

Question:
The region in the first quadrant bounded by the graphs f(x)=(1/8)(x)^3 and g(x)=2x is rotated about the y-axis. Find the volume of the solid formed.

I know the integral basics.
I think I have to place the y points and I think I am meant to convert the y= into x= so I have a x equation.

This is what I got after integrating etc.

((6144/50)*(pi))-((512/12)*pi)).
This I guess is not right.
Thanks for any help.

Originally Posted by Awsom Guy

Question:
The region in the first quadrant bounded by the graphs f(x)=(1/8)(x)^3 and g(x)=2x is rotated about the y-axis. Find the volume of the solid formed.

using washers ...




using cylindrical shells ...

Then I guess I do the normal Solving the function by subbing in the x values. thanks.