LinkBack URL
About LinkBacks
I really don't know where to start with this since theere is no f(t) equation. Please help!
I suspect it was not the difference between "f(x)" and "f(t)" that was rawkstar's problem. I suspect he simply means that he is not given a formula for f(x).
And that's the problem with memorizing formulas rather than learning concepts. You don't need to know the formula if you really understand what is being asked- you read the answers off the graph.
For example, the "concavity" tells how the slope of the graph is changing. A function is "concave upward" as long as the first derivative is increasing.
a) By the "fundamental theorem of calculus", the first derivative ofis, simply, f(x). Looking at the graph, f(x) is increasing between -2 and -1, decreasing for x between -1 and 3/2, then increasing again for x between 3/2 and 3.
b) If the equation of the tangent line to y= G(x) at x= 0 is y= mx+ b, then m is the derivative of G(x) at x= 0 which means it is the value of f(x) at x= 0 which can be read off the graph.
Of course, the "b" is G(0) and that is the area under the graph of f(x) from -2 to 0. And that is the area of a rectangle of height 2 and base 2 plus the area of a semi- circle of radius 1.
c) The "average value" of a function f(x) on [a, b] is.
You are told that, on 0 to 3, the average value of f(x) is 0- that tells you thatso that
. And
.
And you have already found G(0) in (b).
That was a really good explanation but would you please help me understand the second part of b.Originally Posted by HallsofIvy
We are given that the equation of the line tangent to the graph of G(x) at the point where x=0 is y = mx + 7. So shouldn't G(0) be 7?
  |
