using taylor polynomials including binomial series show that: [x(1-x/6)^-3]/(e^x)-1 =1+Kx^3+...... where k is to be determined. (I got 1/216 for k)
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Originally Posted by goaway716 using taylor polynomials including binomial series show that: [x(1-x/6)^-3]/(e^x)-1 =1+Kx^3+...... where k is to be determined. (I got 1/216 for k) I agree with that answer.
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