hi may i know why if g(r(t))=0 or constant then it implies that r'(t) (grad g) = 0 for all values of t?
Last edited by alexandrabel90; March 13th 2010 at 02:48 AM.
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Originally Posted by alexandrabel90 hi may i know why if g(r(t))=0 or constant then it implies that r'(t) (grad g) = 0 for all values of t? By the chain rule, . Since that measures the rate of change of g- and g doesn't change- it is equal to 0.
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