Assuming the emu house is a point (call it A), and the circular boundary intersects the plot of land at points B and C, then ABC is an equilateral triangle. The area enclosed by AB, AC, and the circular boundary is therefore 1/6 the area of a circle with radius 1. Now you just add to this the area of the rest of the plot of land, which is two right triangles with a hypotenuse of 1 and an interior angle of 60 degrees.