Hey guys, hope I can get some help on this problem that I've been stuck on. Find the equation of the tangent line to the given curve at the specific point. y ln y = x, (0,1) Thanks.
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Originally Posted by drahcirnaw Hey guys, hope I can get some help on this problem that I've been stuck on. Find the equation of the tangent line to the given curve at the specific point. y ln y = x, (0,1) Thanks. . So at the point . So now you have the gradient of the tangent and a point on the tangent line. . So the tangent line is .
Originally Posted by drahcirnaw Hey guys, hope I can get some help on this problem that I've been stuck on. Find the equation of the tangent line to the given curve at the specific point. y ln y = x, (0,1) Thanks. Dear drahcirnaw, When I had written my answer Prove it had already posted his one. Therefore I deleted it.
Last edited by Sudharaka; Mar 12th 2010 at 12:19 AM. Reason: The answer is already given
Thanks for the help. Cleared up my problems.
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