I complete the square and get; If I can make the numerator equal to 1, I can use the following rule; But I'm confused as to how to do that.
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Originally Posted by Archduke01 I complete the square and get; If I can make the numerator equal to 1, I can use the following rule; But I'm confused as to how to do that. First write the numerator, 5x- 6 as 5(x- 2)+ 4 so the integral is . Now separate it into two integrals: .
Originally Posted by HallsofIvy First write the numerator, 5x- 6 as 5(x- 2)+ 4 Is there some process you used to come up with that rewrite or is it something I'll simply have to have a feel for? I understand your following steps though, thanks a lot.
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