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Math Help - Maclaurin series for cos^2 (x) help

  1. #1
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    Maclaurin series for cos^2 (x) help

    i understand that the number pattern is 1, -2, 8, -32, etc with values only in the even derivatives and 0.

    However, the actual problem for me is to actually write the series. like i know it would look something like (-1)^n (??x^(2n))/(2n!)

    The ?? I'm having a hard time with since that sequence of numbers (1, -2, 8...) i can't figure out. Thank you
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  2. #2
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    Quote Originally Posted by maximade View Post
    i understand that the number pattern is 1, -2, 8, -32, etc with values only in the even derivatives and 0.

    However, the actual problem for me is to actually write the series. like i know it would look something like (-1)^n (??x^(2n))/(2n!)

    The ?? I'm having a hard time with since that sequence of numbers (1, -2, 8...) i can't figure out. Thank you

    cos^2(x)=\frac{1}{2}+\frac{1}{2}cos(2x).
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  3. #3
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    Yeah thats how i got my values 1,-2, 8, -32, etc. The problem is that I can't find the ?? of (-1)^n (??x^(2n))/(2n!), since that number sequence I can't really figure out
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