so the problem asks us to solve for $\displaystyle \frac{d^2y}{dx^2}$ from the equation
$\displaystyle x^5+y^5=4$
I found $\displaystyle \frac{dy}{dx}=\frac{(-5x^4)}{(5y^4)}$, how would I go about solving for $\displaystyle \frac{d^2y}{dx^2}$?
so the problem asks us to solve for $\displaystyle \frac{d^2y}{dx^2}$ from the equation
$\displaystyle x^5+y^5=4$
I found $\displaystyle \frac{dy}{dx}=\frac{(-5x^4)}{(5y^4)}$, how would I go about solving for $\displaystyle \frac{d^2y}{dx^2}$?