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Math Help - help with integral by parts

  1. #1
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    help with integral by parts

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  2. #2
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by stache31 View Post
    u' = \frac{1}{x}

    v = \frac{46}{3}x^3

    \int u\,dv = uv - \int v\,du

    Your integral is therefore equal to

    \frac{46}{3}x^3 \cdot \ln(x) - \int \left(\frac{46}{3}x^3 \cdot \frac{1}{x}\right)\,dx

    Use algebra to simplify the term inside the brackets, then evaluate the integral which is a standard power rule one
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  3. #3
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    thanks man. also, rammstein is awesome!
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