# Thread: help with integral by parts

1. ## help with integral by parts

2. Originally Posted by stache31
$u' = \frac{1}{x}$

$v = \frac{46}{3}x^3$

$\int u\,dv = uv - \int v\,du$

Your integral is therefore equal to

$\frac{46}{3}x^3 \cdot \ln(x) - \int \left(\frac{46}{3}x^3 \cdot \frac{1}{x}\right)\,dx$

Use algebra to simplify the term inside the brackets, then evaluate the integral which is a standard power rule one

3. thanks man. also, rammstein is awesome!