Results 1 to 2 of 2

Math Help - Surface Area of a Revolution

  1. #1
    Newbie
    Joined
    Feb 2010
    Posts
    15

    Surface Area of a Revolution

    Problem: Find the surface area of revolution about the x-axis of over the interval .

    I got that y' = 30cos(6x)

    and
    S.A. = 10\pi \int_0^{\pi/6} sin(6x)\sqrt{1+900cos(6x)^2}

    But can't figure out how to do that integral. Is the integral wrong?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member Miss's Avatar
    Joined
    Mar 2010
    From
    Planet earth.
    Posts
    165
    Quote Originally Posted by twoteenine View Post
    Problem: Find the surface area of revolution about the x-axis of over the interval .

    I got that y' = 30cos(6x)

    and
    S.A. = 10\pi \int_0^{\pi/6} sin(6x)\sqrt{1+900cos(6x)^2}

    But can't figure out how to do that integral. Is the integral wrong?
    It should be cos^2(6x) not cos(6x)^2.

    use u=cos(6x).
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Surface area of a revolution
    Posted in the Calculus Forum
    Replies: 7
    Last Post: March 27th 2011, 02:47 PM
  2. Area of Surface of Revolution
    Posted in the Calculus Forum
    Replies: 6
    Last Post: February 7th 2010, 12:38 PM
  3. Area of a Surface of Revolution
    Posted in the Calculus Forum
    Replies: 2
    Last Post: March 15th 2009, 10:51 AM
  4. The area of surface of revolution
    Posted in the Calculus Forum
    Replies: 2
    Last Post: November 10th 2008, 06:27 AM
  5. area of surface of revolution
    Posted in the Calculus Forum
    Replies: 6
    Last Post: June 10th 2008, 07:24 PM

Search Tags


/mathhelpforum @mathhelpforum