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Math Help - Value of Taylor Series

  1. #1
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    Value of Taylor Series

    I am stuck on finding out the value of two terms of the Taylor series for this equation:

    x^5e^{x^3}

    and also that this Taylor Series is centered near x = 0 and at this point, the first few terms of this series looks like:

    x^5+x^8+\frac {x^{11}} {2!}+\frac {x^{14}} {3!}+ \frac {x^{17}} {4!}+....

    Finally, I am supposed to determine the values at the 1st and 11th term, again near x = 0.

    Wouldn't both terms be 0 though since the value is dependent upon the x value, which is 0, or am I missing something? Thanks for the help.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by Spudwad View Post
    I am stuck on finding out the value of two terms of the Taylor series for this equation:

    x^5e^{x^3}

    and also that this Taylor Series is centered near x = 0 and at this point, the first few terms of this series looks like:

    x^5+x^8+\frac {x^{11}} {2!}+\frac {x^{14}} {3!}+ \frac {x^{17}} {4!}+....

    Finally, I am supposed to determine the values at the 1st and 11th term, again near x = 0.

    Wouldn't both terms be 0 though since the value is dependent upon the x value, which is 0, or am I missing something? Thanks for the help.
    You are probably missing something, please post the exact wording of the problem.

    CB
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  3. #3
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    Hi Spudwad,

    The function value (for x=0) is only not zero for the (3n+5)th derivative. With n is a real positive integer. This meas that only the (3n+6)th terms in de serie are not equal to zero.

    Since 1 and 11 are both not a (3n+6) term, they have to be zero.

    Good luck!
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