$\displaystyle \int x^5cos(x^3)dx$

dv = cos(x^3)

u= x^5

v = sin x^3 / 3

du = 5x^4

With those settings I can see that I'm going to have to integrate by parts several times, and by several I mean more than 4 times. Is there a faster way to solve this problem that I don't realize?