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Math Help - not sure if this is the correct thread

  1. #1
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    Angry please delete this thread

    i k now this may not seem like a typical calculus question but it was one of the problems in my text.

    z^2 = x^2 + (y^2)/4 identify and sketch.

    i thought this shape would be a cone, but my answer was incorrect. any help?
    Last edited by mr fantastic; March 11th 2010 at 02:04 PM. Reason: Restored deleted question
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  2. #2
    Junior Member autumn's Avatar
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    hello

    seeing as no one else has answered...
    its evudentaly a three dimensinal shape because there are three figures.
    z (to the second power) = x (to the second) + y (to the second)/4
    4z (to the second) = 4x (to the second) + y (to the second)
    the square root of y (to the second) = the square root of -4x (to the second + 4z (to the second)
    my first instinct was that it was a cone. but i would go with a sphear.
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  3. #3
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    Quote Originally Posted by greencheeseca View Post
    i k now this may not seem like a typical calculus question but it was one of the problems in my text.

    z^2 = x^2 + (y^2)/4 identify and sketch.

    i thought this shape would be a cone, but my answer was incorrect. any help?
    Try drawing the level curves for different values of z .....

    (It's NOT a sphere by the way).
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