i k now this may not seem like a typical calculus question but it was one of the problems in my text.

z^2 = x^2 + (y^2)/4 identify and sketch.

i thought this shape would be a cone, but my answer was incorrect. any help?

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- Mar 11th 2010, 11:08 AMgreencheesecaplease delete this thread
i k now this may not seem like a typical calculus question but it was one of the problems in my text.

z^2 = x^2 + (y^2)/4 identify and sketch.

i thought this shape would be a cone, but my answer was incorrect. any help? - Mar 11th 2010, 12:18 PMautumnhello
seeing as no one else has answered...

its evudentaly a three dimensinal shape because there are three figures.

z (to the second power) = x (to the second) + y (to the second)/4

4z (to the second) = 4x (to the second) + y (to the second)

the square root of y (to the second) = the square root of -4x (to the second + 4z (to the second)

my first instinct was that it was a cone. but i would go with a sphear. - Mar 11th 2010, 03:11 PMmr fantastic