# not sure if this is the correct thread

• Mar 11th 2010, 10:08 AM
greencheeseca
i k now this may not seem like a typical calculus question but it was one of the problems in my text.

z^2 = x^2 + (y^2)/4 identify and sketch.

i thought this shape would be a cone, but my answer was incorrect. any help?
• Mar 11th 2010, 11:18 AM
autumn
hello
seeing as no one else has answered...
its evudentaly a three dimensinal shape because there are three figures.
z (to the second power) = x (to the second) + y (to the second)/4
4z (to the second) = 4x (to the second) + y (to the second)
the square root of y (to the second) = the square root of -4x (to the second + 4z (to the second)
my first instinct was that it was a cone. but i would go with a sphear.
• Mar 11th 2010, 02:11 PM
mr fantastic
Quote:

Originally Posted by greencheeseca
i k now this may not seem like a typical calculus question but it was one of the problems in my text.

z^2 = x^2 + (y^2)/4 identify and sketch.

i thought this shape would be a cone, but my answer was incorrect. any help?

Try drawing the level curves for different values of z .....

(It's NOT a sphere by the way).