Hi, I have a very basic question to ask. The Integral is
(P^-1) dt from 0 to t. Can I rewirte it as lnP(at t) - lnP(at 0)? Where P is pressure and is varying with time.
Please help?
Dear lalleykhan,
If you had t instead of p you could write it as lnt. That is,
$\displaystyle \int^{t_{1}}_{t_{2}}{\frac{1}{t}}dt=\ln{t_{1}}-\ln{t_{2}}$
But in this case you cannot do so. But do you know the relation between P and t? If so we could try to solve the integral.
Dear lalleykhan,
Ok. Then you can draw a graph between $\displaystyle \frac{1}{p}~vs.~t$. That is your y axis must be 1/p and your x axis must be t. So if you find the area bounded by this curve and the x axis from 0 to t you can get $\displaystyle \int^{t}_{0}{\frac{1}{p}dt}$
Hope this will help you.