Just bummed on this question here.. :
∫(pi/ax+b)dx
Thanks so much!
Step by step teaching if possible.. Thank you so much. I want to learn!
Dear gearshifter,
$\displaystyle \int{\frac{\pi}{ax+b}} dx $
Since you could take constants out of the integration sign,
$\displaystyle \int{\frac{\pi}{ax+b}} dx=\pi\int{\frac{1}{ax+b}} dx $
Therefore, $\displaystyle \int{\frac{\pi}{ax+b}} dx =\pi\int{\frac{1}{ax+b}} dx=\frac{\pi\ln(ax+b)}{a}+C$ ; Where C is an arbitary constant.
Hope this will help you.