Question: $\displaystyle \int \frac{dx}{x^2+6x+10}$ If it was $\displaystyle -6x$ I believe the method is to complete the square but not sure with $\displaystyle +6x$... Would like some tips please
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You would still complete the square. $\displaystyle x^2+6x+10=(x+3)^2+1$, so we have $\displaystyle \int \frac{dx}{(x+3)^2+1}=\int \frac{du}{u^2+1}$ (letting $\displaystyle u=x+3$). Can you go from here?
Yah I got it, thanks a lot I have been feeling dumb a lot lately after some of my posts here...
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