Math Help - Integration Question (inverse trig)

1. Integration Question (inverse trig)

Question:
$\int \frac{dx}{x^2+6x+10}$

If it was $-6x$ I believe the method is to complete the square but not sure with $+6x$...

Would like some tips please

2. You would still complete the square.

$x^2+6x+10=(x+3)^2+1$, so we have

$\int \frac{dx}{(x+3)^2+1}=\int \frac{du}{u^2+1}$ (letting $u=x+3$).

Can you go from here?

3. Yah I got it, thanks a lot I have been feeling dumb a lot lately after some of my posts here...