Results 1 to 3 of 3

Math Help - Integration Question (inverse trig)

  1. March 10th 2010, 07:42 PM #1
    jfinkbei
    jfinkbei is offline
    Newbie
    Joined
    Jan 2010
    Posts
    14

    Integration Question (inverse trig)

    Question:
    \int \frac{dx}{x^2+6x+10}

    If it was -6x I believe the method is to complete the square but not sure with +6x...

    Would like some tips please
    Follow Math Help Forum on Facebook and Google+
  2. March 10th 2010, 07:51 PM #2
    Black
    Black is offline
    Member Black's Avatar
    Joined
    Nov 2009
    Posts
    105
    You would still complete the square.

    x^2+6x+10=(x+3)^2+1, so we have

    \int \frac{dx}{(x+3)^2+1}=\int \frac{du}{u^2+1} (letting u=x+3).

    Can you go from here?
    Follow Math Help Forum on Facebook and Google+
  3. March 10th 2010, 07:53 PM #3
    jfinkbei
    jfinkbei is offline
    Newbie
    Joined
    Jan 2010
    Posts
    14
    Yah I got it, thanks a lot I have been feeling dumb a lot lately after some of my posts here...
    Follow Math Help Forum on Facebook and Google+
« very simple Fourier series question | Related Rates »

Similar Math Help Forum Discussions

  1. Integration question relating to inverse trig functions.
    Posted in the Calculus Forum
    Replies: 12
    Last Post: January 5th 2011, 02:37 AM
  2. integration of inverse trig.
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: November 17th 2009, 06:23 AM
  3. more integration of inverse trig
    Posted in the Calculus Forum
    Replies: 1
    Last Post: November 4th 2009, 04:04 AM
  4. inverse trig integration
    Posted in the Calculus Forum
    Replies: 5
    Last Post: July 10th 2009, 07:04 PM
  5. Inverse Trig Integration
    Posted in the Calculus Forum
    Replies: 3
    Last Post: September 10th 2008, 08:44 PM

Search Tags


/mathhelpforum @mathhelpforum