# Math Help - Integration Question (inverse trig)

1. ## Integration Question (inverse trig)

Question:
$\int \frac{dx}{x^2+6x+10}$

If it was $-6x$ I believe the method is to complete the square but not sure with $+6x$...

$x^2+6x+10=(x+3)^2+1$, so we have
$\int \frac{dx}{(x+3)^2+1}=\int \frac{du}{u^2+1}$ (letting $u=x+3$).