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Math Help - very simple Fourier series question

  1. #1
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    very simple Fourier series question

    simple for anyone but myself obviously or else I wouldn't be posting it here!

    I know the simple rule cos(n\pi) = (-1)^n
    but is there a similarly simple way of writing
    cos (n \frac{\pi}{2})
    and
    sin (n \frac{\pi}{2})
    ?
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  2. #2
    Member Black's Avatar
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    \cos\left(\frac{n\pi}{2}\right)=\frac{i^n}{2}(1+(-1)^n)

    \sin\left(\frac{n\pi}{2}\right)=\frac{i^{n-1}}{2}(1-(-1)^n)
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