Hi - I didn't know whether this thread should go in the Chat Room, Pre-Calculus or Calculus forum, so feel free to move it to wherever appropriate.

In studying exponential/logarithmic functions in my pre-calculus class, I realized something about logarithmic growth which lead to some sort of paradox (btw, I've taught myself a fair amount of Calculus on my own for preparation - I'm sure this question is resolved in those classes, but anyway..):

A simple feature of the natural logarithm function, $\displaystyle ln(x)$, is that as $\displaystyle x\rightarrow\infty \Longrightarrow ln(x)\rightarrow\infty$.

Assuming the differentiation and integration formulas for transcendental functions are true without proof here, $\displaystyle \frac{d}{dx} ln(x) = \frac{1}{x}$.

A simple feature of the reciprocal function, $\displaystyle \frac{1}{x}$, is that as $\displaystyle x\rightarrow\infty \Longrightarrow \frac{1}{x}\rightarrow0$.

So how is it then, that $\displaystyle ln(x)\rightarrow\infty$ as $\displaystyle x\rightarrow\infty$ when its rate of change (on interval $\displaystyle x > 1$) modeled by its derivative, $\displaystyle \frac{1}{x}$ with respect to the same argument $\displaystyle x$, goes to 0?

In other words, how is it possible that as $\displaystyle x\rightarrow\infty \Longrightarrow ln(x)\rightarrow\infty$ when as as the same time $\displaystyle x\rightarrow\infty \Longrightarrow \frac{1}{x}\rightarrow0$?

I understand the basic principal behind logarithmic growth, that the function tends to infinity, but grows extremely slowly, and gets slower proprotional to its argument. Not unlike how the exponential function grows extremely fast, and gets faster proportional to its argument. But it's paradoxical nonetheless in regards to logarithmic growth. Exponential growth does not have this paradox, as its derivative (rate of change) goes to infinity as the function itself does ($\displaystyle \frac{d}{dx}e^x = e^x.$).

Not that it really matters, I just thought it was rather interesting. It relates in some sense I believe to how we define a natural logarithm as the definite integral $\displaystyle \int\frac{1}{x} dx$ (bounds 1 to x - I don't know how to use Latax for definite integrals). Similarly, as x grows, the area drawn out by the curve $\displaystyle \frac{1}{x}$ grows smaller and smaller as x grows larger and larger, so the logarithm function's growth is in some sense tending to 0; but how can it grow to infinity in that case as we're taught it does?