Find the second Taylor approximation for the following

g(x)=ln(cos)(x))

I think I have to use the chain rule, but i'm not sure how. I really need help.

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- Mar 10th 2010, 03:30 AMtim_mannireTaylor approximation
Find the second Taylor approximation for the following

g(x)=ln(cos)(x))

I think I have to use the chain rule, but i'm not sure how. I really need help. - Mar 10th 2010, 03:33 AMMiss
- Mar 10th 2010, 03:38 AMtim_mannire
yes, i believe taylor series and taylor approximation mean the same thing.

- Mar 10th 2010, 03:41 AMMiss
centered at what?

- Mar 10th 2010, 06:19 AMCaptainBlack
- Mar 10th 2010, 07:46 AMBrandong954
Wouldn't it just be -ln(x^2/2!)?

How I got my answer was just by identifying that cos(x) = 1 - x^2/2!, then just take the ln of each nth. This left me with 0 - ln(x^2/2!).

Please keep in my that I could be wrong, fore I am learning Taylor/MacLaurin series at this moment. - Mar 10th 2010, 07:52 AMDrexel28
- Mar 10th 2010, 07:55 AMDrexel28