$\displaystyle \int 16sin^2 x cos^2 x dx$

Would someone like to help a confused AB Calc Student?

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- Mar 9th 2010, 02:57 PMpenguinpwnOne more for tonight, then I'll leave you guys alone...
$\displaystyle \int 16sin^2 x cos^2 x dx$

Would someone like to help a confused AB Calc Student? - Mar 9th 2010, 03:01 PMDrexel28
- Mar 9th 2010, 03:14 PMpenguinpwn
Could you please explain where the third step you have shown came from?

- Mar 9th 2010, 03:16 PMDrexel28
- Mar 9th 2010, 03:19 PMpenguinpwn
Ok, i get it now the double angle formula. Thanks for clarifying for me =)

- Mar 9th 2010, 03:22 PMDrexel28