I'm new to the forum and having a tough time on some of my homework problems and was looking for some feedback.

So here's one of my problems.

Use implicit differentiation to find the slope of the tangent line to the curve

$\displaystyle \frac{y}{x-6y}=x^3-3$

at the point $\displaystyle (1,\frac{-2}{-11})$

I'm just having trouble finding a starting point. Any help is greatly appreciated.