Evaluate the limit of

$\displaystyle \lim_{x \to \pi} \frac {sin^2{x}} {1+cos{3x}} $

I assume I use L'Hopital's rule here?

This gives me:

$\displaystyle \frac {sin{2x}} {-3sin{3x}} $

which comes to 0/0.

wanting some reassurance here that I'm on the right track! (Itwasntme)