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Math Help - integration and differential

  1. #1
    Junior Member
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    integration and differential

    the differential equation is 2+5sin(4πt/25)
    so after the integration, i get 2t-5cos(4πt/25)(25/4π)
    so i wanna get the value in the interval from 0 to 6)

    so i put 2+5sin(4πt/25) on my calculator and made it do the integration,
    It gives me 31.8159
    but when i F(6)-F(0) on this function, 2t-5cos(4πt/25)(25/4π), i get something entirely different.
    My calculator is on radian mode and π is pie
    What am i doing wrong?
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  2. #2
    Member Miss's Avatar
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    Quote Originally Posted by hangainlover View Post
    the differential equation is 2+5sin(4πt/25)
    This is not an equation.
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