Question:

$\displaystyle \int x.3^x dx$

Attempt:

u=x , dv=$\displaystyle 3^x$

du =dx , v=$\displaystyle \frac{3^x}{ln3}$

= $\displaystyle x.\frac{3^x}{ln3}-\int \frac{3^x}{ln3} dx$

How to integrate the last part ??

Please answer in steps , Thank you