# Thread: Circles in Triangles Limit Problem

1. ## Circles in Triangles Limit Problem

Let T be the equilaterall triangle with sides = 1 length.

Let $a_{n}$ be the # of circles that can be packed tightly in n rows inside the triangle.

$
a_{1} = 1
$

$
a_{2} = 3
$

$
a_{3} = 6
$

$
a_{4} = 10
$

Let $A_{n}$ be the combined area of the $a_{n}$ circles. Find the limit of $A_{n}$ as n -> infinity.

I believe I have to find a series for the number of circles in the triangles, right? So I need to find something to represent 1, 3, 6, 10, 15 ... ?

2. Without giving it much thought, it seems like the limit should just be the area of the triangle, which is $\frac{1}{2}$

EDIT: Nevermind. I misread your question. A formula that might help you is that $a_n=\frac{n(n+1)}{2}$ Try to find a formula for $A_n$ For example, $A_1=a_1*\pi*\frac{3}{16}$

3. How did you get the 3/16 part? A = pi * r^2 so I know it's r^2 but I just want to make sure I'm on the same page.

4. Yes that is the r^2. Draw a picture and it might be clearer. $(\frac{\sqrt{1^2-.5^2}}{2})^2=\frac{3}{16}$

5. When I attempt to get one circle's radius squared, I get 3/12 so I'm confused.

Also I still don't know how to get a formula for An.